Electric Circuit, Kirchhoff's Law (0421)

Electric Circuit, Kirchhoff's Law

The image show above is electrical circuit. Also porf.Mason asked the brightness of the light bulbs when the switch was closed. The light bulbs theoretically had the same brightness. However, since the lower light bulb was defective, the brightness did not come out as we expect

That is our prediction. Because the voltage difference between two side of bulb is zero, so the bulb doesn't light.

Theoretically, the two bulb have same brightness, because the voltage difference cross the bulb is same.

That's our answer.

That's our set up.

We were filling the table on the lab manual. Our jobs were to find the potential difference for each set up

We using the color band code compare measurement, the measurement almost in the range.

Here we were trying to simplify the combination of resistors by making them as like one equivalent resistor. 

For parallel: R_eq= (1/R1+1/R2+...1/Rn)^-1

For series: R_eq= R1+R2+..+Rn

Kirchhoff's Law applying.

Today we went back to study electric circuit. This time we emphasized on theoretical side rather than just knowing how to set the wire up as we did in the last lab. We learned about the Kirchhoff's rule in circuit along with the process of how to equivalent resistors (we believe that we can apply the same process to find the intensity also).